Two letters in the word 'LEMON' have as many | vedclass

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(C) The word is '$LEMON$'.Let us check the positions of the letters in the alphabet:$L$ is the $12^{th}$ letter,$E$ is the $5^{th}$ letter,$M$ is the

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$M$

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(C) The word is '$LEMON$'.Let us check the positions of the letters in the alphabet:$L$ is the $12^{th}$ letter,$E$ is the $5^{th}$ letter,$M$ is the $13^{th}$ letter,$O$ is the $15^{th}$ letter,and $N$ is the $14^{th}$ letter.We look for pairs of letters that have the same number of letters between them as in the English alphabet.$1$. Between $L$ and $M$: In '$LEMON$',there is one letter $(E)$ between them. In the alphabet,there is one letter ($L, M$ are $12^{th}$ and $13^{th}$,so zero letters between them). This does not match.$2$. Between $L$ and $N$: In '$LEMON$',there are three letters $(E, M, O)$ between them. In the alphabet,there is one letter $(M)$ between $L$ and $N$. This does not match.$3$. Between $M$ and $N$: In '$LEMON$',there are zero letters between them. In the alphabet,$M$ and $N$ are consecutive,so there are zero letters between them. This is a match.Between the pair $(M, N)$,$M$ comes earlier in the alphabet ($13^{th}$ position) than $N$ ($14^{th}$ position).

Two letters in the word '$LEMON$' have as many letters between them in the word as in the alphabet. Which one of the two letters comes earlier in the alphabet?

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Two letters in the word '$LEMON$' have as many letters between them in the word as in the alphabet. Which one of the two letters comes earlier in the alphabet?

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